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Topic: [SteamPunk Crescendo] Mechanical Conundrum
Started by: dindenver
Started on: 3/30/2009
Board: First Thoughts


On 3/30/2009 at 5:35pm, dindenver wrote:
[SteamPunk Crescendo] Mechanical Conundrum

Hi!
 OK, this is basically a gut check.

  The system I am making will use a modified version of Otherkind (I already checked with Vincent and he is cool with it).

  The idea is, you roll 3 dice and after the roll assign one to Ambition, Cunning and Protection. You compare those to a target number determined by your opponent and from that you get successes. Ideally, it is my cunning roll against your protection stat. My Protection roll against your cunning stat and Ambition vs ambition. So, if I roll Cunning 2 higher than your Protection, I get a +2 success and that is the base harm you take. there is more to it than that, but this is a good overview.

  So, its is a game with Regular People (tm), magic, superscience and vampires.

  I want to allow players to add +1 to some dice and get bonus dice as needed.

  I ran the numbers and it looks like:
Bonus to one die - Increases the overall average number of successes, but does not increase the chances of getting successes on all three dice as much as bonus dice do.
Bonus Dice - They increase the likelihood of getting successes on all three dice, but does not raise the average number of successes as much as getting a bonus to one die does.

  So, what I want to do is assign one mechanic to mundane things (skill, traits, etc.) and one mechanic to kewl powers (magic, superscience, vampire powers, etc.).

  My gut tells me that acing all three dice is more "powerful" than getting a higher overall average. While getting a higher overall average is more "skillful" than getting successes on all three dice.

  Does that seem logical? Are there mathematical anomalies I am not seeing?

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On 3/30/2009 at 9:14pm, Egonblaidd wrote:
Re: [SteamPunk Crescendo] Mechanical Conundrum

First off, let me say that I'm not familiar with Otherkind and not entirely sure I understand your system (though I think I do), and besides that I could just be making a mathematical blunder, but it seems to me that your assessment of the bonus die is not quite right, that the bonus die is more powerful.  I have a d6 right here (actually, I have a d4, d8, a whole bunch of d10s, a d12, and a d20, but I assume you meant a d6 for your system), so what I'm going to do is roll it and actually see how a bonus to one die and a bonus die change things.  The bonus die will be enclosed in [ ].
I'm making some assumptions here.  First, that the target numbers are unknown, and therefore increasing the average of all the dice increases the average number of successes for all three dice.  Second, I'm assuming there is no reason not to swap the lowest die with the bonus die if the bonus die is higher.

First roll: 2, 1, 4, [4]
Now, with no bonus, the dice average is 2.33.  If we apply the +1 then the average is 2.67.  If we swap the 1 with the bonus die, the average is 3.33.  Hence, since the average of all three dice is higher the average number of successes should be much higher.  Also, the 4 is much more likely to be a success than the 1.

Second roll: 4, 5, 4, [3]
This is an interesting case.  The bonus die is no good here, since it is lower than all the other numbers.  With no bonus, the average is 4.33, with the +1 to one die the average is 4.67.  A 5+1=6 should beat or tie with anything, but a 4+1=5 should give better chances of all around success.

Third roll: 5, 6, 2, [4]
As we can see here, the best deal is to swap the lowest die with the bonus die, rather than get a +1 bonus.  The only exception was if you specifically wanted to max out that 5, rather than applying it to the 2.  Consequently, the average is also 4.33 with no bonus, 4.67 with the +1, and 5 with the bonus die.

Alright, now I'm starting to think you may be right.  The question is, what is the probability that one of the three dice will end up lower than the bonus die?  I'm not sure I have a firm grasp of probability, but as I read on Wikipedia, the chance of A or B happening is the probability of A plus the probability of B.  Therefore, the chance of any of the three dice A, B, and C coming up as a given number is 0.167+0.167+0.167=0.5.  The chance of the bonus die coming up with a specific number is 0.167 (or 1/6).  So, there is a 50% chance one of the three dice will be a 1, and a 5/6 chance that the bonus die will then be higher.  I think this will have to be on a case by case basis.  Here's the equation we need, the chance that A and B or A and C or B and C will be greater than or equal to x, times the chance of x coming up on the remaining die.  So 3[(6-x+1)(6-x+1)/36](1/6).
In the table below, I have the lowest of the three dice, the chance that that will be the lowest, and the chance that the bonus die will be higher.
[table][tr][td][table][tr][td]Lowest of 3 dice[/td][/tr][tr][td]1[/td][/tr][tr][td]2[/td][/tr][tr][td]3[/td][/tr][tr][td]4[/td][/tr][tr][td]5[/td][/tr][tr][td]6[/td][/tr][/table][/td][td][table][tr][td]Chance[/td][/tr][tr][td]50%[/td][/tr][tr][td]34.72%[/td][/tr][tr][td]22.22%[/td][/tr][tr][td]12.5%[/td][/tr][tr][td]5.56%[/td][/tr][tr][td]1.39%[/td][/tr][/table][/td][td][table][tr][td]Bonus Die[/td][/tr][tr][td]83.33%[/td][/tr][tr][td]66.67%[/td][/tr][tr][td]50%[/td][/tr][tr][td]33.33%[/td][/tr][tr][td]16.67%[/td][/tr][tr][td]0%[/td][/tr][/table][/td][/tr][/table]
I make no claim as to the accuracy of this table, so someone please correct me if I'm wrong.  And yes, I suddenly realize how beneficial a probability course could be, I'll consider taking one if I can fit it into my last year here at college (though honestly I'll bet modern geometries is way more fun).
To get the chance of that bonus die actually being useful, I have no idea where to go from here, sorry.

In any case, you're probably right, the bonus die will be more powerful.  So it sounds like a good idea to go with your gut here.

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On 3/30/2009 at 9:50pm, dindenver wrote:
RE: Re: [SteamPunk Crescendo] Mechanical Conundrum

Phil,
 Thanks for your response. So, I basically, just laid out a spreadsheet with all the die combos and counted successes (for the test, I used 5 and higher).
  I guess this only holds true IF the +1 bonus is added only to dice that are at success-1.
  Some numbers:
With 4d6 taking in all the combos, there are 1296 results (6^4)

With 3 dice no mods, I get the following numbers:
Average number of successes (1.00)
Number of times all three dice come up successes (48)
Number of rolls with one or more success (912)

With 4 dice no mods take the highest three, I get the following numbers:
Average number of successes (1.32)
Number of times with three dice come up as successes (144)
Number of rolls with one or more success (1040)

With 3 dice with one +1 applied to any one result that is (success-1), I get the following numbers:
Average number of successes (1.42)
Number of times all three dice come up successes (120)
Number of rolls with one or more success (1134)

4 dice with one +1 applied to any one result that is (success-1), take the highest three, I get the following numbers:
Average number of successes (1.81)
Number of times with three dice come up as successes (312)
Number of rolls with one or more success (1215)

  So, if I gave you a bonus die, would you trade it in for a +1, before the die was cast?

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